Knibbsworth":zbg11sml said:I have read this before in a book by John Douglas of the FBI. As another poster has identified, the OP is referring to the Monty Hall problem. Once you have established behind one door is a goat, you take it back to the start. You had 3 possibilities:
If you had Goat 1 originally, if you stick you keep Goat 1. You know the other door is Goat 2 now. If you twist, you get a Ferrari.
If you had the other goat it is the same. Stick, you keep Goat 2. You know behind the other door is Goat 1. Twist you get a Ferrari.
If you have a Ferrari, then stick you keep it. Twist you will get either Goat 1 or 2.
There were 3 scenarios, and in two of them twisting gets the star prize. If there was an even 33.3% chance before you were given a door, then there is a 66.6% chance that switching will benefit you.
Good explanation, and using it as a basis I am going to have another go at an explanation to see if I can further help any of the doubters!
SWITCHING
If you choose the Ferrari first time (1 in 3 chance) then you end up with a goat if you switch
If you choose a goat first time (2 in 3 chance) then you end up with a Ferrari if you switch
So switching results in a Ferrari in 2 out of 3 scenarios
STICKING
If you choose the Ferrari (1 in 3 chance) and stick you win the ferrari
If you choose a goat (2 in 3 chance) and stick you win a goat
So sticking results in a Ferrari in 1 out of 3 scenarios
Thus... you are twice as likely to win the Ferrari if you switch than if you stick.
The gutting thing though is that if you DO (unknowingly) pick the Ferrari at the outset and then switch (as you should) then you lose the Ferrari and feel terrible.